60 * (1.08)^9 + 60
total number of guitars at end of 10 months
I’m someone who loves math. But I can’t seem to figure out this problem. I’m helping someone with their math homework, and I can’t even find this concept on Google to try to work it out. Here’s the question and the answer:
Problem:
Answer:
If you can clearly explain to me…
http://askmemathsquestions.tumblr.com/post/23679711437/solution
check this out
Also, another equation:
(2x+1)squared-5(2x+1)+6=0
let 2x+1 = u
equation is now
u^2 -5u + 6 = 0
giving u = -3 and u =-2
put u = 2x+1
ie 2x+1 = -3, 2x+1 = -2
x= -2 and x = -3/2
A vegetable garden measures 8 ft. by 12ft. By what equal amount must each dimension be increased if the area is to be doubled?
The option for the answers are:
a.) 2 ft
b.) 4 ft
c.) 6 ft
d.) 8 ft
Thanks!
the quadratic formed using the conditions of the above word problem is (x+8)(x+12) = 2*8*12
giving x = -24 or x = 4
hence, x= 4 is your answer.
8.The anti-derivative of dx/(1-x)^2 from 0 to 3
is
(a) -3/2
(b) -1/2
(c) 1/2
(d) 32
(e) divergent
let 1-x =u
-dx= du
ie dx= -du
so your integral now changes from dx/(1-x)^2 to
-du/(u^2)
this you can evaluate.
substitute u = 1-x in your final answer, put your limits of integration in place, and you will have your answer.
if the pic in unclear, use this link
assuming a linear relationship between price and quantity demanded,
p - 10 = m(q - 27000),
where p is price, q is quantity demanded, and m is the slope of the line
this is the point slope form of an equation of a line.
Now, the slope is simply m = (10-8)/(27000-33000) = -1/3000, so our equation becomes:
p - 10 = -1/3000(q - 27000)
Revenue is simply the price times to quantity, or:
r = pq
Let’s solve our demand equation for q:
q = -3000(p-10)+27000
Now sub this into r=pq:
r = [-3000(p-10)+27000]*p
To maximize revenue, take the derivative and solve for dr/dp=0
dr/dp = r’(p) = -3000(p-10)+27000 - 3000p, solve:
0 = -3000(p-10)+27000 - 3000p = -6000p + 57000
p = -57000/-6000 = 9.5
What this means is that we need to set the price of a ticket at $9.50 to maximize our revenue. This is represented by p=9.5, r=270750
I tried this problem many times already and I’m still stuck. I’m really close to the right answer, but still not there. Can you help me, please? :)
P(x) ≈ P(a) + P’(a) (x-a)
where a is chosen so that P(a) is exact .
take a = 64, in your case
then
P(x) = 596 x^(-1/2)
P’(x) = -298 x^(-3/2)
P(64) = 74.5
P’(64) = -149/256
P(x) = 74.5 - 149/256 (x - 64)
now, you can get P(60) - P(59) .
hope that helps
Question 1: A rectangle with its base on the x-axis is inscribed in the region bounded by the curve f(x)=x^2 and the line x=4. Find the dimensions of the rectangle with the maximal area
Question 2: A rectangle swimming pool is 10meters long and 6 meters wide. It has a depth of 1 meter at the…
ans 1
the aera of rectangle can be safely assumed as (4-x)*x^2
x=8/3 gives maximum area
